TS EAMCET 2015 Solved Paper

Section: Mathematics

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Question : 36 of 160

Marks: +1, -0

The equation of the parabola with focus (1,−1) and directrix x+y+3=0 is

x2+y2−10x−2y−2xy−5=0
x2+y2+10x−2y−2xy−5=0
x2+y2+10x+2y−2xy−5=0
x2+y2+10x+2y+2xy−5=0

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