TS EAMCET 20-July-2022 Shift 2 Solved Paper

Let r= radius of large drop and R= radius of each of small drops

As volume remains same, Initial volume = Final volume
‌

4

3

πr3=8×‌

4

3

πR3
⇒‌‌r=2R or R=‌

r

2

Change in surface area due to splitting of drop is
∆A‌=8×4πR2−4πr2
‌=8×4π(‌

r

2

)2−4πr2
‌=4πr2
∴ Work done =S.∆A=S⋅4πr2=4πr2S