The line x+2 y-c=0 meets the curve x^{2}+y^{2}-3 x-6 y+3=0 at two points {P} and {Q} and \angle{POQ}=\frac{\pi}{2}, where {O} is the origin. Then, 2 c^{2}-15 c=

TS EAMCET 20-July-2022 Shift 2 Solved Paper

Section: Mathematics

Question : 49 of 160

Marks: +1, -0

The line x+2y−c=0 meets the curve x2+y2−3x−6y+3=0 at two points P and Q and ∠POQ=‌

, where O is the origin. Then, 2c2−15c=

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