TS EAMCET 20-July-2022 Shift 2 Solved Paper

On comparing corresponding components,
7+3β‌=5α+3
⇒‌‌3β‌=5α−4....(i)
−3‌=5+6β+3γ
⇒‌‌3γ=−8−6β
⇒‌‌3γ=−10α.....(ii)
3α+3γ=−5+3β+9
‌3α+3γ=−5+3β+9
⇒‌‌3α=4+3β−3γ ....(iii)
On putting the values from Eqs. (i) and (ii) into Eq. (iii), we get
‌3α=4+(5α−4)−(−10α)
⇒‌‌3α=5α+10α
⇒‌‌α=0
From Eq. (i), 3β=0−4
⇒‌‌β=‌

−4

3

From Eq. (ii), 3γ=0
‌⇒‌‌γ=0