TS EAMCET 20-July-2022 Shift 2 Solved Paper

⇒‌

x2−x+1

(x2+1)(x2+x+1)

On comparing the corresponding coefficients
A+C‌=0......(i)
A+B+D‌=1......(ii)
A+B+C‌=−1......(iii)
B+D‌=1 ......(iv)
From Eqs. (i)and (iii), we have
B=−1
From Eq. (iv), we have
‌−1+D=1
⇒‌‌D=2
From Eq. (ii), we have
A+(−1)+2‌=1
A‌=0
From Eq. (i), we have
A+C=0
0+C=0
C=0
∴‌‌A+2B+C+2D
‌=0+2(−1)+0+2(2)
‌=−2+4=2