TS EAMCET 20-July-2022 Shift 2 Solved Paper

Given, word is TSEAMCET
In the word, T and E occur twice. So, we have S, A, M, C, TT, EE. We have 6 distinct letter.
Way 1 4 letters selected and all are distinct.
‌6C4=‌6C2=‌

6×5

2×1

=15
Way 2 2 letters are alike and 2 are distinct
‌2C1×‌5C2=2×‌

5×4

2×1

=20
Way 3 2 letters are alike and rest 2 are also alike ‌2C2=1
So, the total number of ways =15+20+1=36