TS EAMCET 20-July-2022 Shift 2 Solved Paper

The transformed equation is
8x3−54x−78=0
Root of cubic equation f(x)=0 are diminished by
‌

−3

2

Since, we don't have the original equation but the transformed equation. Therefore, we will verify it through the option.
On taking option (a), we have
‌f(x)=2x3−9x2−6
‌f(x)=2x3−9x2+0x−6∴‌A0y3+A1y2+A2y+A3=0
‌2y3+0y2+(‌

−27

2

)y−‌

39

2

=0
⇒2y3−‌

27y

2

−‌

39

2

=0
⇒8y3−54y−78=0
⇒8x3−54x−78=0
which is the transformed equation.