The {E}^{\circ} of {Ce}^{4+} \/ {Ce}^{3+}=1.6 {V} {Fe}^{3+} \/ {Fe}^{2+}=0.76 {V} the {E}^{\circ} of {Fe}^{3+} oxidising {Ce}^{3+} is

TS EAMCET 20-July-2022 Shift 2 Solved Paper

Section: Chemistry

Question : 144 of 160

Marks: +1, -0

The E∘ of Ce4+∕Ce3+=1.6V
Fe3+∕Fe2+=0.76V
the E∘ of Fe3+ oxidising Ce3+ is

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