If \frac{3 \pi}{4}< x< \frac{7 \pi}{4} then \int(2^x-\sqrt{1+\sin 2 x}+\frac{1}{x^2}-\frac{1}{x}) d x=

Correct Answer is : 2xlog2+sinx−cosx−1x−logx+c

\frac{2^x}{\log 2}-\sin x+\cos x-\frac{1}{x}-\log x+c

2^x \log 2+\sin x-\cos x-\frac{1}{x}+\frac{1}{x^2}+c

\frac{2^x}{\log 2}+\sin x-\cos x-\frac{1}{x}-\log x+c

2^x \log 2-\sin x+\cos x-\frac{1}{x}+\frac{1}{x^2}+c

TS EAMCET 20-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

If ‌

3π

<x<‌

7π

then ∫(2x−√1+sin‌2‌x+‌

−‌

)dx=

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