If the line 2 x-3 y+4=0 cuts the ellipse x=3 \cos \theta, y=5 \sin \theta in {A} and {B} and (\alpha, \beta) is the midpoint of \overline{ {AB}}, then 3 \beta-2 \alpha=

TS EAMCET 20-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 59 of 160

Marks: +1, -0

If the line 2x−3y+4=0 cuts the ellipse x=3‌cos‌θ,y=5‌sin‌θ in A and B and (α,β) is the midpoint of AB, then 3β−2α=

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