If 2 \overline{i}+4 \overline{j}-5 \overline{k}, \overline{i}+\overline{j}+\overline{k}, \overline{j}+2 \overline{k} are the position vectors of the vertices {A}, {B}, {C} of a triangle respectively, then a unit vector along the median drawn through the vertex {A} is

Correct Answer is : 1√214(3i+6j−13k)

\frac{1}\sqrt{174}(5 \overline{i}+10 \overline{j}-7 \overline{k})

\frac{1}\sqrt{214}(3 \overline{i}+6 \overline{j}-13 \overline{k})

\frac{1}\sqrt{66}(\overline{i}+\overline{j}-8 \overline{k})

\frac{1}{7}(3 \overline{i}+6 \overline{j}-2 \overline{k})

TS EAMCET 20-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 30 of 160

Marks: +1, -0

If 2i+4j−5k,i+j+k,j+2k are the position vectors of the vertices A,B,C of a triangle respectively, then a unit vector along the median drawn through the vertex A is

‌
1
√174
(5i+10j−7k)
‌
1
√214
(3i+6j−13k)
‌
1
√66
(i+j−8k)
‌
1
7
(3i+6j−2k)

Validate

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