TS EAMCET 20-July-2022 Shift 1 Solved Paper

The given situation is shown belowMagnitude of force on a length l of wire a due to ' current carrying parallel wire b,
Fab=‌

µ0

2π

⋅‌

iaib

d1

×l (Attractive)
Similarly, magnitude of force on a length l of wire a due to current carrying wire c,
Fac=‌

µ0

2π

‌

iaic

d2

×l‌ (Repulsive) ‌
∴ Net magnetic force on a length of the wire a,
F‌net ‌=Fac−Fab
‌=‌

µ0

2π

‌

iaic

d2

×l−‌

µ0

2π

‌

iaib

d1

×l
‌=‌

µ0

2π

⋅‌

ia×4ia×l

2d1

−‌

µ0

2π

⋅‌

ia×ia×l

d1

‌=‌

µ0ia2l

2πd1

(since, d2=2d1,ib=ia and ic=4ia )