TS EAMCET 20-July-2022 Shift 1 Solved Paper

Maximum speed of wave is given as
vmax=ωA
= Angular speed × Amplitude
Thus,
In option (a) y(x,t)=2sin‌(2x−2t)
‌A=2,ω=2
∴‌‌vmax=2×2=4m∕ s
In option (b), y(x,t)=3sin‌(2x−3t)
A‌=3,˙ω=3
∴‌‌vmax‌=3×3=9m∕ s
In option (c),y(x,t)=2sin‌(3x−2t)
A=2,ω=2
∴vmax=2×2=4m∕ s
In option (d), y(x,t)=3sin‌(5x−2t)
A‌=3,ω=2
∴‌‌vmax‌=3×2=6m∕ s
Clearly, wave speed is maximum as 9m∕ s in wave equation given in option (b).