© examsiri.com
Question : 96 of 160
Marks:
+1,
-0
Solution:
Given, mass of
CO2,m=176g Atomic mass of
CO2,M=12+16×2=44 ∴ Number of mole of
CO2 n=‌=‌=4 Change in temperature,
∆T=30−0=30∘C=30KHeat absorbed,
Q=3600J We know that,
Q=ns∆T ⇒‌‌3600‌=4×s×30⇒s=‌‌=30Jmol−1K−1
© examsiri.com
Go to Question: