TS EAMCET 19-July-2022 Shift 2 Solved Paper

The given situation is shown below.The two cars A and B are moving with same speed as 25‌km‌/‌h in the direction shown in the above figure.From the diagram,
Relative velocity of car‌B with respect to car A, i.e. vBA is 25√2‌km∕h at an angle of 45∘ from east towards north.
∴ Minimum distance between the two cars i.e distance of closest approach is equal
AC=BAsin‌45∘.
=50sin‌45∘=25√2‌km
∴ Time taken=‌

AC

|vBA|

=‌

25√2

25√2

=1h=60‌min