TS EAMCET 19-July-2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 80 of 160

Marks: +1, -0

The general solution of ((1+x2)y‌sin‌x−2xy)dx−log‌y1+x2‌d‌y=0 is

sin‌x−log(1+x2)=log‌y+c
(log‌y)2+2‌cos‌x+log(1+x2)2=c
log‌y=2‌cos‌x+log(1+x2)+c
‌
log‌y
y
=2‌sin‌x+cos‌x‌log(1+x2)+c

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