TS EAMCET 19-July-2022 Shift 2 Solved Paper

Given, equation of parabola y2=16x
LL′=4a=16
End points of latusrectum is (a1±2a) Coordinates of L is (4,8) and L′ is (4,−8). The end points of focal length is
The end points of focal length is
(at2,2at)‌ and ‌(‌a∕t2,−‌2a∕t)
Coordinate of P is (1,4)
⇒at2=1,‌2at=4
⇒4t2=1,‌2×4×t=4
⇒‌‌t2=‌

1

4

,‌‌t=‌

1

2

∴‌‌t=‌

1

2

∴Coordinate of Q ‌(‌

4

(1/2)2

,−‌

2×4

(1/2

)=(16,−16)
‌=√720=12√5