Let {A}=[\table 0 , 0 , -1 ; 0 , -1 , 0 ; -1 , 0 , 0], {B}=[\table 0 , 1 , 0 ; 1 , 0 , 0 ; 0 , 0 , 1] then ( {A}^{-1} {B})^{-1}+( {AB}^{-1})^{-1}=

Correct Answer is : [0−2000−2−200]

\left[\begin{array}{ccc}1 & 0 & 0 \ 0 & -2 & 0 \ 0 & 0 & 2]\end{array}

\left[\begin{array}{ccc}0 & -2 & 0 \ 0 & 0 & -2 \ -2 & 0 & 0]\end{array}

\left[\begin{array}{ccc}-2 & 0 & 0 \ 0 & 0 & -2 \ 0 & -2 & 0]\end{array}

[\table 0 , 0 , -2 ; -2 , 0 , 0 ; 0 , -2 , 0]

TS EAMCET 19-July-2022 Shift 2 Solved Paper

Section: Mathematics

Question : 5 of 160

Marks: +1, -0

Let A=[

],B=[

] then (A−1B)−1+(AB−1)−1=

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