TS EAMCET 19-July-2022 Shift 2 Solved Paper

Let the line L intersect X-axis at a point (h,0).
Slope of line L(m1)=‌

0+3

h−5

=‌

3

h−5

Slope of line (m2),√3x+y−9=0 is −√3
tan‌60∘=|‌

‌ 3 h−5 +√3

1−‌ 3√3 h−5

|
When √3=‌

3+√3(h−5)

h−5−3√3

⇒‌‌√3h−5√3−9=3+√3h−5√3 (Not possible)
When √3=‌

−(3+√3(h−5))

h−5−3√3

‌⇒‌‌√3h−5√3−9=−3−√3h+5√3
‌⇒‌‌2√3h=10√3+6⇒h=5+√3
The line L intersect X-axis at point (5+√3,0). Equation of line L is
⇒‌‌√3x−y−5√3−3=0