TS EAMCET 19-July-2022 Shift 2 Solved Paper

Comparing the coefficients on both sides, we get
A+C=0⇒A=−C.....(i)
and
B+D=1......(ii)
3A+C=0
From Eq. (i), we get A=C=0
3B+D=−2.....(iii)
On subtracting Eq. (ii) from Eq. (iii), we get
2B=−3
⇒‌‌B=−‌

3

2

D=1−(−‌

3

2

)   [ ∵ from Eq. (ii)]
=‌

5

2