TS EAMCET 19-July-2022 Shift 2 Solved Paper

Given, number of silicon atom,
nSi=5×1028‌ atoms ‌∕m3
Number of arsenic atom,
nAs‌=4.5×1021‌atom∕m3
ni‌=1.5×1016∕m3
Number of free electrons obtained from
‌ doping ‌=ne=nAs=4.5×1021‌ electrons ‌∕m3
∴ Total number of electrons after doping,
N=ne+ni‌=4.5×1021+1.5×1016
‌=1.5×1016(3×105+1]
‌=1.5×1016(3×105)=4.5×1021
According to mass-action law,
ne⋅mh=ni2
⇒‌‌nh=5×1010‌holes∕m3