TS EAMCET 19-July-2022 Shift 1 Solved Paper

Radius of wheel, R=0.5m
Moment of inertia of wheel, I=10‌kg−m2
Initial angular velocity =2π×‌

70

60

‌rad∕ s
⇒‌‌ω0=‌

14π

6

‌rad∕ s
t=5 s, final angular velocity, ω=0
Using equation of rotational motion,
ω=ω0+αt
⇒‌‌α=‌

ω−ω0

t

=‌

0− 14π 6

5

=‌

14π

30

‌rad∕ s2
∴ Torque on the wheel,
τ=Iα=10×‌

14

30

π=‌

14π

3

N−m
⇒‌‌τ=‌

14π

3

But torque on the wheel to stop it,
τ′=F×R=88×0.5=44N−m
Coefficient of kinetic friction between wheel and wet cloth,
µ=‌

τ

τ′

=‌

‌ 14π 3

44

=0.33