Given that \frac{d}{d x}(Tan^{-1} x)=\frac{1}{1+x^{2}} and \frac{d}{d x}(Sinh^{-1} x)= {1}/\sqrt{1+x^{2}}. Then \int {3 x^{6}-2 x^{4}+x^{2}-2}/{x^{2}+1} d x=

Correct Answer is : 35x5−53x3+6x−8Tan−1x+c

\frac{3}{7} x^{7}-\frac{2}{5} x^{5}+\frac{1}{3} x^{3}-2 x+c

\binom{\frac{3}{7} x^{7}-\frac{2}{5} x^{5}+\frac{1}{3} x^{3}-2 x}/{{x^{3}}/{3}+x}+c

\frac{3}{5} x^{5}-\frac{5}{3} x^{3}+6 x-8 Tan^{-1} x+c

\frac{3}{5} x^{5}-\frac{5}{3} x^{3}+6 x-8 Sinh^{-1} x+c

TS EAMCET 19-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

Given that ‌

(Tan−1x)=‌

1+x2

and ‌

(Sinh−1x)=‌

√1+x2

. Then ∫‌

3x6−2x4+x2−2

x2+1

dx=

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