TS EAMCET 19-July-2022 Shift 1 Solved Paper

Given, lines are
5x+6y−34=0.....(i)
and 2x+y+c=0......(ii)
Here, l1=5,m1=6,n1=34
l2=2,m2=1,n2=c
And given circle x2+y2−8x−10y+25=0
Here, centre =(−g,−f)=(4,5)
and radius=√g2+f2−c
‌=√16+25−25=4
Since, Eqs. (i) and (ii) are conjugate lines with respect to given circle
‌⇒16=13+c⇒c=3
Now, line 2x+y+c=2x+y+3=0
∴ Point (1,−5) lines on this line.