If the matrix A=[\table 1 , 2 , 2 ; 2 , 1 , 2 ; 2 , 2 , 1] satisfies the matrix equation A^{2}-4 A-5 I=0, then A^{-1}=

Correct Answer is : 15[−3222−3222−3]

\frac{1}{5}[\table -3 , 2 , 2 ; -2 , 3 , -2 ; 2 , 2 , -3]

\frac{1}{5}[\table -3 , 2 , 2 ; 2 , -3 , 2 ; 2 , 2 , -3]

\frac{1}{5}[\table -3 , 2 , 2 ; 2 , -3 , 2 ; -2 , -2 , 3]

\frac{1}{5}[\table -3 , 2 , 2 ; 2 , -3 , 2 ; 2 , 2 , 3]

TS EAMCET 19-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 5 of 160

Marks: +1, -0

If the matrix A=[

] satisfies the matrix equation A2−4A−5I=0, then A−1=

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