TS EAMCET 19-July-2022 Shift 1 Solved Paper

Slope of line BC=‌

5+1

−3−5

=‌

6

−8

=‌

−3

4

Slope of line AD=‌

4

3

  [∵AD⟂BC]
Equation of AD is
‌y−3=‌

4

3

(x−1)
‌3y−9=4x−4
‌4x−3y=−5....(i)
Slope of AC=‌

3+1

1−5

=−1
Slope of BE=1  [BE⟂AC]
Equation of line BE is
‌y−5=1(x+3)
‌y−x+3+5
y=x+8 ....(ii)
Substitute value of y from Eq. (ii) to Eq. (i),
4x−3(x+8)‌=−5
4x−3x−24‌=−5
x‌=19
y‌=27
∴ The coordinate of orthocentre is (19,27).