TS EAMCET 19-July-2022 Shift 1 Solved Paper

Molecular orbital electronic configurations are
‌O2→σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2
‌π*2px1π*2py1
Bond order →‌

6−2

2

=‌

4

2

=2 paramagnetic
O2+→σls2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2π*2px1
Bond order →‌

10−5

2

=‌

5

2

=2.5 paramagnetic
‌O22−→σls2σ*1s2σ2s2σ*2s2σ2pz2π2px2
‌π2py2‌‌π*2px2π*2py2
Bond order =‌

10−8

2

=‌

2

2

=1, diamagnetic
‌˙O2−→σ1s2σ*1s2σ2s2σ*2s2σ2pz2
‌π2px2π2py2π*2px2π*2py1
Bond order =‌

10−7

2

=1.5
=‌

3

2

=1.5, paramagnetic
The species with (A), the highest bond order is O2+ and (B), diamagnetic character is O22−. Hence, option (b) is correct.