TS EAMCET 19-July-2022 Shift 1 Solved Paper

The given arrangement of system of charges are shown as In △ABC,sin‌30∘=‌

BC

AC

⇒‌

1

2

=‌

BC

10

⇒BC=5‌cm
Similarly,
AB‌=ACsin‌60∘=10×‌

√3

2

‌=5√3‌cm
The given charges form two electric dipole of dipole moment p1 and p2 as shown belowand p2=BC×q=5qC−m
The magnitude of dipole moment of the combination
p‌=√p12+p22=√(5√3q)2+(5q)2
⇒‌‌p‌=√100q2=10q