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Question : 66 of 160
Marks:
+1,
-0
Solution:
x3[√x2+√x4+1−√2x]=x3[‌| (√x2+√x4+1−√2x)(√x2+√x4+1+√2x). |
| (√x2+√x4+1+√2x) |
] =x3[‌| x2+√x4+1−2x2 |
| (√x2+√x4+1+√2x) |
] =x3[‌| (√x4+1−x2)(√x4+1+x2) |
| (√x2+√x4+1+√2x)(√x4+1+x2.) |
] =x3[‌| x4+1−x4 |
| (√x2+√x4+1+√2x)(√x4+1+x2) |
] =x3[‌| 1 |
| x(√1+√1+‌+√2)⋅x2(√1+‌+1) |
] =‌| 1 |
| (√1+√1+0)+√2)(√1+0+1) |
=‌=‌ $$
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