TS EAMCET 18-July-2022 Shift 2 Solved Paper

1‌cm=107‌nm
Edge length of original cube =107‌nm
Volume of original cube (V)=(107)3‌nm
Edge length of new cube =1‌nm
Volume of new cube =(1)3‌nm
If the number of new cubes formed is n ,
then volume of total new cubes will be (V1)=n×(1)3‌nm
But V=V1
∴‌‌(107)3=n×(1)3
∴‌‌n=1021
The surface area of the original cube
(S)=6×(107)2nm2=6×a2
The surface area of the total cubes formed after crushing the original cube
‌=(S1)=6×1021×(1)2nm2
‌

S1

S

‌=‌

6×1021×(1)2

6×(107)2

=107