TS EAMCET 18-July-2022 Shift 1 Solved Paper

The given situation is shown below

where, p0= atmospheric pressure,
R= Air bubble of radius =1‌mm,ρ= density of liquid =2000‌kg∕m3
and T= surface tension of liquid =0.1N∕m .
Now, we know that, excess pressure inside an air bubble inside any liquid =‌

2T

R

Also, pressure inside the air bubble = pressure outside _ excess pressure
⇒Pinside=

P0

atmospheric pressure

+

pgh

pressure due to liquid column

+

2T R

excess pressure inside air bubble

Difference of pressure inside the air bubble and atmospheric pressure,
⇒p‌inside ‌−p0‌=ρgh+‌

2T

R

‌=2000×10×‌

8

100

+‌

2×0.1

1×10−3

‌=1600+(2×100)
‌=1800N∕m2