TS EAMCET 18-July-2022 Shift 1 Solved Paper

Given,
m‌=100g=0l‌kg
∆t‌=2‌ms=2×10−3 s
Initial speed, u=10m∕ s
Let final speed be v .
We know that, area under force-time graph gives impulse or change in momentum.
∴ Area of the triangle =|∆p|
(where, p= momentum)
⇒‌

1

2

× Base × Height =|pf−pi

‌

‌

|
(where, pf= final momentum and pi= initial momentum)
⇒‌

1

2

×(2×10−3)×(20×1000)=0.1v−0.1u
(∵20‌kN=20000N)
⇒‌‌2×10=0l(v−10)‌‌(∵u=10m∕ s)
⇒‌‌v−10=200
⇒‌‌v=210m∕ s