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Question : 77 of 160
Marks:
+1,
-0
Solution:
Let
I=‌(‌+log(‌))‌dxLet
f(x)=‌(‌+log(‌))f(−x)=‌(‌+log(‌))=‌(‌−log(‌))f(x)+f(−x)=‌I=f(x)‌dx=f(x)+f(−x)‌dx=‌‌‌‌dxI=‌‌‌‌dx=‌‌‌‌dx=‌‌‌‌dxOn putting
tan‌x=tI=‌‌‌=‌⋅‌[tan−1√3t]01=‌[tan−1√3−0]I=‌×‌=‌⇒I2=‌3I2=4
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