If \alpha, \beta, \gamma are the roots of the equation 3 x^{3}-26 x^{2}+52 x-24=0 such that \alpha, \beta, \gamma are in geometric progression and \alpha < \beta < \gamma, then 3 \alpha+2 \beta+\gamma=

TS EAMCET 18-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 13 of 160

Marks: +1, -0

If α,β,γ are the roots of the equation 3x3−26x2+52x−24=0 such that α,β,γ are in geometric progression and α<β<γ, then 3α+2β+γ=

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