TS EAMCET 18-July-2022 Shift 1 Solved Paper

Expression for the magnetic field of EM wave is given as
B=(2×10−8)‌cos[π×1015(t+‌

y

c

)]‌

^

k

T
Magnitude of magnetic field vector,
B0=2×10−8T
Magnitude of electric field vector of EM wave,
E0=B0c
where, c is speed of light
‌=2×10−8×3×108
‌=6V∕m‌‌(∵c=3×108m∕ s)
If

^

n

be the unit vector along the direction of electric field, then we know that unit vector along electric field vector x
Unit vector along magnetic field vector = Unit vector along the direction of propagation of EM wave.
i.e.

^

n

×

^

k

=−

^

j

clearly, ‌‌

^

n

=

^

i

Hence, expression of electric field vector of EM wave,
E=6‌cos[π×1015(t+‌

y

c

)]‌

^

i

V∕m