TS EAMCET 18-July-2022 Shift 1 Solved Paper

Given, number of turns per cm in long solenoid, n=20 turns ∕cm=2000 turns ∕m
Area of loop, A=‌

4

π

cm2=‌

4

π

×104m2
∆I=3−1=2A
‌∆t=0.2 s
∴ Magnetic field inside the solenoid mm
B=µ0nI‌‌‌⋅⋅⋅⋅⋅⋅⋅(i)
Magnetic flux linked with loop kept inside the solenoid normal to it,
φ‌=BA
‌=µ0nIA [from Eq. (i)]
∴ According to Faraday's law of electromagnetic induction, magnitude of induced emf is given as
|e|=‌

dφ

dt

=‌

d

dt

(µ0nLA)=µ0nA‌

dI

dt

⇒|e|=µ0nA.‌

∆I

∆t

=4π×10−7×2000×‌

4

π

×10−4×‌

2

0.2

=3.2×10−6V
‌=3.2µV (∵10−6V=1µV)