TS EAMCET 14-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

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Question : 79 of 160

Marks: +1, -0

The general solution of the differential equation

dy

dx

=

2x−3y+4

3x+2y−7

is

x2+y2=3xy+y+C
(2x−3y)2+(3x+2y)2=C
x2+y2+3xy−4x−7y+C=0
x2−3xy−y2+4x+7y+C=0

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