TS EAMCET 14-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

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Question : 43 of 160

Marks: +1, -0

If aα2+bβ2+cαβ+d=0 is the transformed equation of 4x2+√3xy+5y2−4=0 obtained using α=

√3

2

x+

y

2

and β=−

x

2

+

√3

2

y, then c(a+b+d)=

0
13√3
5√3
6

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