TS EAMCET 14-Sep-2020 Shift 2 Solved Paper

Wavelength for Lyman series is calculated as
‌

1

λ

=R(‌

1

12

−‌

1

n2

)
For first line of Lyman series, n=2
∴‌

1

λ

=R(‌

1

12

−‌

1

22

)⇒‌

1

λ

=‌

3R

4

⇒‌‌&λ=‌

4

3R

⇒R=‌

4

3λ

Wavelength of Balmer series is calculated as
‌

1

λ′

=R(‌

1

22

−‌

1

n2

)
For first line of Balmer series, n=3
∴‌

1

λ′

=R(‌

1

22

−‌

1

32

)
⇒‌

1

λ′

=‌

5

36

R⇒‌

1

λ′

=‌

5

36

×‌

4

3λ

‌‌‌ [from Eq. (i)] ‌
⇒‌

1

λ′

=‌

5

27λ

⇒λ′=‌

27λ

5