TS EAMCET 14-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

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Question : 75 of 160

Marks: +1, -0

lim[

n

3

2

n

5

2

−

n

1

2

n

3

2

+

n

3

2

(n+2)

5

2

−

n

3

2

(n+4)

5

2

−

n

1

2

(n+6)

3

2

+....,,,+

n

3

2

(n+2(n−1))

5

2

−

n

1

2

(n+3(n−1))

3

2

]=

−√2
3
−1
9√3
√2
3
1
9√3

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