TS EAMCET 14-Sep-2020 Shift 1 Solved Paper

Given, circle
(x−a)2+y2=a2 and x2+(y−a)2=a2
Common chord of circle is
(x−a)2−x2+y2−(y−a)2=0
End point of chord is (0,0),(a,a)
Mid-point of chord is (‌

a

2

,‌

a

2

)
∴(I) is true
Length of common chord is √a2+a2=√2a
Intersection point of common chord is (0,0) and (a,a)
Distance from centre to common chord is