TS EAMCET 14-Sep-2020 Shift 1 Solved Paper

∴W=‌

EQ

F

=‌

‌ A n ×Q

F

⇒‌‌A′×h×d=‌

A×Q

nF

⇒Q=‌

(A′×h)×d×n×F

A

[∵ Volume of Cu-deposited on the nickel block = area of the block × thickness of copper layer
Where, d= density of Cu=8.9g/cm3
n=2‌‌[∵Cu2++2e−→Cu↓]
F=96500Cmol−1
A= atomic weight of Cu*=635gmol−1
[* In data informations,
Given, density of CuSO4=8.9g/cc
If is wrong : it will be density of Cu=8.9g/cc]