TS EAMCET 14-Sep-2020 Shift 1 Solved Paper

Newly prepared radioactive sample shows 4 times the allowed and safe value of radioactivity, so on reaching to the allowed and safe value, its radioactivity will be reduced to (‌

1

4

) th of the current value,
∵‌‌At=‌

A

(2)t/t1∕2

Here, A= current activity, At= final activity =‌

A

4

t= time-taken, t1/2= half-life =24h
So, on putting the values
‌

A

4

=‌

A

(2)t/t1/2

⇒(2)t/t1/2=4