TS EAMCET 14-Sep-2020 Shift 1 Solved Paper

The given situation is shown belowFor, refraction through a spherical surface
‌

µ2

v

−‌

µ1

u

=‌

µ2−µ1

R

⇒‌‌‌

1.5

v

−‌

1

(−45)

=‌

1.5−1

(+15)

⇒‌‌‌

1.5

v

=‌

3−2

90

⇒‌

1.5

v

=‌

1

90

⇒‌‌v=1.5×90=+135cm
Image will be formed at right side of separating interface at a distance of 135cm from it.