TS EAMCET 11-Sep-2020 Shift 2 Solved Paper

Given the solution,
ax2+by2=1
Now differentiating Eq. (i) W.r.t. x, we get
2ax+2by‌

dy

dx

=0 or ‌

y

x

(‌

dy

dx

)=−‌

a

b

Again differentiating w.r.t. x, we get
This is the differential equation of order 2 and degree 1 obtained from the solution (1).
∴ Comparing with αx2+βy2=1
α=2,β=1⇒2x2+y2=1
or ‌

x2

(‌ 1 2 )

+‌

y2

1

=1⇒a2=‌

1

2

,b2=1
Eccentricity,