TS EAMCET 11-Sep-2020 Shift 2 Solved Paper

Given equation of parabola, y2=16x and all the vertices are of an equilateral triangle with one of them coincides with the vertex of parabolaSince, given parabola is symmetrical about X -axis
So, ∠AOM=30∘
In ∴ Coordinate of point A lying on parabola is
(4(2√3)2,8(2√3))≡(48,16√3)
∴ Distance OA=√(xA−x0)2+(yA−y0)2
=√(48−0)2+(16√3−0)2
OA=32√3
∴ Length of the side of equilateral triangle =32√3.