TS EAMCET 11-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

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Question : 27 of 160

Marks: +1, -0

In a triangle ABC, if c=9, s=10 and Δ=10√2 then b[1+√2tan(

A−B

2

)]=

a[1−√2tan(
A−B
2
)]
c[1−√2tan(
A−B
2
)]
a[√2tan(
A−B
2
)−1]
c[√2tan(
A−B
2
)−1]

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