TS EAMCET 11-Sep-2020 Shift 2 Solved Paper

Section: Mathematics
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Question : 18 of 160
 
Marks: +1, -0
If sum of the coefficients of xr(r=0,1,2,........2n) in the expansion of (1+3x−2x2)n, is 128, then
2n
Σ
r=1
r
(2n)cr
(2n)cr−1
=
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