The two capacitors of 5µF each are in parallel. So, their equivalent capacitance is (5+5)10µF. Similarly, two 2µF capacitors are also in parallel. So, their equivalent capacitance is (2+2)4µF. The circuit is now reduced to as shown
In steady state, when all the capacitors are charged, no current flow in the circuit. So, potential across resistors is zero. As in parallel combination, potential is same in both wires CD and BG, i.e. 100V. In series combination, the potential is divided between the capacitor in the inverse ratio of their capacitance, i.e. ‌