TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

Potential energy of a body performing SHM is given by
U=‌

1

2

kx2
Here, x is the displacement of the body from mean position.
Given, ‌‌x=‌

a

2

‌‌[a= amplitude ]
Now, kinetic energy of this body is given by
K=‌

1

2

mv2=‌

1

2

mω2(a2−x2)
⇒‌‌K=‌

1

2

K(a2−x2)
Given, ‌‌x=‌

a

2

From Eqs. (i) and (ii), we get
‌

K

U

=‌

‌ 1 2 k× 3a2 4

1 2 k×‌ a2 4

=‌

3

1